-(3/2)^x+12=2x-3

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Solution for -(3/2)^x+12=2x-3 equation: 



-(3/2)^x+12=2x-3

We move all terms to the left:

-(3/2)^x+12-(2x-3)=0



Domain of the equation: 2)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(+3/2)^x-(2x-3)+12=0

We get rid of parentheses

-(+3/2)^x-2x+3+12=0

We multiply all the terms by the denominator


-(+3-2x*2)^x+3*2)^x+12*2)^x=0

We add all the numbers together, and all the variables

-(-2x*2+3)^x+3*2)^x+12*2)^x=0

Wy multiply elements

12x^2-(-2x*2+3)^x=0

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